Correlation between USRBDX output and mgdrawBDX

Dear expert,

In some cases, when outputs (position, energy, direction cosine) of mgdrawBDX are not enough to get good statistics in a two step process, writing a probability distribution using USRBDX can be an alternative way. For each solid angle (either in radian or degree) bin, we get energy distribution. In this context, I am not aware how these solid angles are defined (is it with respect to the origin of the geometry ? ) or how these solid angles are related to the direction cosines (like we get from mgdrawBDX output) . Can you please provide some insight ?

Thanks and regards,
Riya

Dear @riya,

USRBDX scorings can be used to score double differential particle distributions across a boundary surface. This double-differential is in energy and angle. The angle is defined with respect to the normal of the boundary surface between 2 adjacent regions. The angular distribution is intended as the distributions in the solid angle with (1-cos(theta)). Theta is the angle between the particle trajectory and the normal to the boundary at the point of crossing.

For complete information on the use of USRBDX, please, refer to the manual:
https://flukafiles.web.cern.ch/manual/USRBDX.html

Cheers,
Anna

Thank you @cimmino for the explanation. So from USRBDX output, position sampling is not possible right? , since if two particles at different position are entering a boundary (let’s say a sphere) with same angle with the normal drawn at their respective position, they will be registered in the same angular bin, right ??

Thanks and regards,
Riya

Hi @riya

Yes, you are correct in your statement

Cheers,
Anna

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